Given that FGHK is a rhombus, calculate
- ∠p
- ∠r
(a)
∠FLK = ∠GLN = 101° (Vertically opposite angles)
∠p
= 180° - 101° - 24°
= 55° (Angles sum of triangle)
(b)
∠KHG
= 180° - 24° - 24°
= 132° (Angles sum of triangle)
∠r
= 360° - 101° - 132° - 24°
= 103° (Sum of Angles in a quadrilateral)
Answer(s): (a) 55°; (b) 103°