Given that DEFG is a rhombus, calculate
- ∠l
- ∠n
(a)
∠DHG = ∠EHK = 98° (Vertically opposite angles)
∠l
= 180° - 98° - 22°
= 60° (Angles sum of triangle)
(b)
∠GFE
= 180° - 22° - 22°
= 136° (Angles sum of triangle)
∠n
= 360° - 98° - 136° - 22°
= 104° (Sum of Angles in a quadrilateral)
Answer(s): (a) 60°; (b) 104°