Given that BCDE is a rhombus, calculate
- ∠h
- ∠k
(a)
∠BFE = ∠CFG = 108° (Vertically opposite angles)
∠h
= 180° - 108° - 13°
= 59° (Angles sum of triangle)
(b)
∠EDC
= 180° - 13° - 13°
= 154° (Angles sum of triangle)
∠k
= 360° - 108° - 154° - 13°
= 85° (Sum of Angles in a quadrilateral)
Answer(s): (a) 59°; (b) 85°
