Given that CDEF is a rhombus, calculate
- ∠k
- ∠l
(a)
∠CGF = ∠DGH = 99° (Vertically opposite angles)
∠k
= 180° - 99° - 19°
= 62° (Angles sum of triangle)
(b)
∠FED
= 180° - 19° - 19°
= 142° (Angles sum of triangle)
∠l
= 360° - 99° - 142° - 19°
= 100° (Sum of Angles in a quadrilateral)
Answer(s): (a) 62°; (b) 100°