Given that ABCD is a rhombus, calculate
- ∠g
- ∠h
(a)
∠AED = ∠BEF = 98° (Vertically opposite angles)
∠g
= 180° - 98° - 12°
= 70° (Angles sum of triangle)
(b)
∠DCB
= 180° - 12° - 12°
= 156° (Angles sum of triangle)
∠h
= 360° - 98° - 156° - 12°
= 94° (Sum of Angles in a quadrilateral)
Answer(s): (a) 70°; (b) 94°