Given that ABCD is a rhombus, calculate
- ∠g
- ∠h
(a)
∠AED = ∠BEF = 106° (Vertically opposite angles)
∠g
= 180° - 106° - 12°
= 62° (Angles sum of triangle)
(b)
∠DCB
= 180° - 12° - 12°
= 156° (Angles sum of triangle)
∠h
= 360° - 106° - 156° - 12°
= 86° (Sum of Angles in a quadrilateral)
Answer(s): (a) 62°; (b) 86°