Given that BCDE is a rhombus, calculate
- ∠h
- ∠k
(a)
∠BFE = ∠CFG = 99° (Vertically opposite angles)
∠h
= 180° - 99° - 20°
= 61° (Angles sum of triangle)
(b)
∠EDC
= 180° - 20° - 20°
= 140° (Angles sum of triangle)
∠k
= 360° - 99° - 140° - 20°
= 101° (Sum of Angles in a quadrilateral)
Answer(s): (a) 61°; (b) 101°