Given that EFGH is a rhombus, calculate
- ∠n
- ∠p
(a)
∠EKH = ∠FKL = 99° (Vertically opposite angles)
∠n
= 180° - 99° - 18°
= 63° (Angles sum of triangle)
(b)
∠HGF
= 180° - 18° - 18°
= 144° (Angles sum of triangle)
∠p
= 360° - 99° - 144° - 18°
= 99° (Sum of Angles in a quadrilateral)
Answer(s): (a) 63°; (b) 99°