Given that CDEF is a rhombus, calculate
- ∠k
- ∠l
(a)
∠CGF = ∠DGH = 110° (Vertically opposite angles)
∠k
= 180° - 110° - 22°
= 48° (Angles sum of triangle)
(b)
∠FED
= 180° - 22° - 22°
= 136° (Angles sum of triangle)
∠l
= 360° - 110° - 136° - 22°
= 92° (Sum of Angles in a quadrilateral)
Answer(s): (a) 48°; (b) 92°