Given that BCDE is a rhombus, calculate
- ∠h
- ∠k
(a)
∠BFE = ∠CFG = 103° (Vertically opposite angles)
∠h
= 180° - 103° - 23°
= 54° (Angles sum of triangle)
(b)
∠EDC
= 180° - 23° - 23°
= 134° (Angles sum of triangle)
∠k
= 360° - 103° - 134° - 23°
= 100° (Sum of Angles in a quadrilateral)
Answer(s): (a) 54°; (b) 100°