Given that CDEF is a rhombus, calculate
- ∠k
- ∠l
(a)
∠CGF = ∠DGH = 110° (Vertically opposite angles)
∠k
= 180° - 110° - 20°
= 50° (Angles sum of triangle)
(b)
∠FED
= 180° - 20° - 20°
= 140° (Angles sum of triangle)
∠l
= 360° - 110° - 140° - 20°
= 90° (Sum of Angles in a quadrilateral)
Answer(s): (a) 50°; (b) 90°