Given that BCDE is a rhombus, calculate
- ∠h
- ∠k
(a)
∠BFE = ∠CFG = 110° (Vertically opposite angles)
∠h
= 180° - 110° - 12°
= 58° (Angles sum of triangle)
(b)
∠EDC
= 180° - 12° - 12°
= 156° (Angles sum of triangle)
∠k
= 360° - 110° - 156° - 12°
= 82° (Sum of Angles in a quadrilateral)
Answer(s): (a) 58°; (b) 82°