Given that BCDE is a rhombus, calculate
- ∠h
- ∠k
(a)
∠BFE = ∠CFG = 109° (Vertically opposite angles)
∠h
= 180° - 109° - 15°
= 56° (Angles sum of triangle)
(b)
∠EDC
= 180° - 15° - 15°
= 150° (Angles sum of triangle)
∠k
= 360° - 109° - 150° - 15°
= 86° (Sum of Angles in a quadrilateral)
Answer(s): (a) 56°; (b) 86°