Given that ABCD is a rhombus, calculate
- ∠g
- ∠h
(a)
∠AED = ∠BEF = 103° (Vertically opposite angles)
∠g
= 180° - 103° - 16°
= 61° (Angles sum of triangle)
(b)
∠DCB
= 180° - 16° - 16°
= 148° (Angles sum of triangle)
∠h
= 360° - 103° - 148° - 16°
= 93° (Sum of Angles in a quadrilateral)
Answer(s): (a) 61°; (b) 93°