Given that BCDE is a rhombus, calculate
- ∠h
- ∠k
(a)
∠BFE = ∠CFG = 111° (Vertically opposite angles)
∠h
= 180° - 111° - 14°
= 55° (Angles sum of triangle)
(b)
∠EDC
= 180° - 14° - 14°
= 152° (Angles sum of triangle)
∠k
= 360° - 111° - 152° - 14°
= 83° (Sum of Angles in a quadrilateral)
Answer(s): (a) 55°; (b) 83°