Given that BCDE is a rhombus, calculate
- ∠h
- ∠k
(a)
∠BFE = ∠CFG = 111° (Vertically opposite angles)
∠h
= 180° - 111° - 22°
= 47° (Angles sum of triangle)
(b)
∠EDC
= 180° - 22° - 22°
= 136° (Angles sum of triangle)
∠k
= 360° - 111° - 136° - 22°
= 91° (Sum of Angles in a quadrilateral)
Answer(s): (a) 47°; (b) 91°