The table shows the distance Mr Yeo jogged each day over a period of 4 days. The distance Mr Yeo jogged follows a pattern. Based on the pattern, what is the distance Mr Yeo jogged on Day 11?
| Day |
1 |
2 |
3 |
4 |
| Distance jogged |
400 m |
500 m |
600 m |
700 m |
Pattern for the distance jogged:
Day 1: 400 + 0 x 100 = 400 m
Day 2: 400 + 1 x 100 = 500 m
Day 3: 400 + 2 x 100 = 600 m
Day 4: 400 + 3 x 100 = 700 m
Formula:
Distance jogged = 400 + (Day number - 1) x 100
Distance jogged on Day 11
= 400 + (11 - 1) x 100
= 400 + 10 x 100
= 1400 m
Answer(s): 1400 m
