The table shows the distance Mr Cheong jogged each day over a period of 4 days. The distance Mr Cheong jogged follows a pattern. Based on the pattern, what is the distance Mr Cheong jogged on Day 8?
| Day |
1 |
2 |
3 |
4 |
| Distance jogged |
400 m |
450 m |
500 m |
550 m |
Pattern for the distance jogged:
Day 1: 400 + 0 x 50 = 400 m
Day 2: 400 + 1 x 50 = 450 m
Day 3: 400 + 2 x 50 = 500 m
Day 4: 400 + 3 x 50 = 550 m
Formula:
Distance jogged = 400 + (Day number - 1) x 50
Distance jogged on Day 8
= 400 + (8 - 1) x 50
= 400 + 7 x 50
= 750 m
Answer(s): 750 m
