A sum of $1188 is divided among a group of people.
56 of the people receive $9 each,
12 of the remainder receive $6 each and the rest receive $3 each. How many people are there altogether?
$9 |
$6 |
$3 |
5 x 2 |
1 x 2 |
|
1 |
1 |
10 u |
1 u |
1 u |
|
$9 |
$6 |
$3 |
Number |
10 u |
1 u |
1 u |
Value |
$9 |
$6 |
$3 |
Total value |
90 u |
6 u |
3 u |
Fraction of people who did not receive $9
= 1 -
56 =
16 Fraction of the remainder who received $3
= 1 -
12 =
12 Fraction of people who received $6
=
16 x
12 =
112 Fraction of people who received $3
=
16 x
12 =
112Total amount of money received
= 90 u + 6 u + 3 u
= 99 u
99 u = 1188
1 u = 1188 ÷ 99 = 12
Number of people who received the money
= 10 u + 1 u + 1 u
= 12 u
= 12 x 12
= 144
Answer(s): 144