A sum of $561 is divided among a group of people.
34 of the people receive $7 each,
12 of the remainder receive $6 each and the rest receive $3 each. How many people are there altogether?
$7 |
$6 |
$3 |
3 x 2 |
1 x 2 |
|
1 |
1 |
6 u |
1 u |
1 u |
|
$7 |
$6 |
$3 |
Number |
6 u |
1 u |
1 u |
Value |
$7 |
$6 |
$3 |
Total value |
42 u |
6 u |
3 u |
Fraction of people who did not receive $7
= 1 -
34 =
14 Fraction of the remainder who received $3
= 1 -
12 =
12 Fraction of people who received $6
=
14 x
12 =
18 Fraction of people who received $3
=
14 x
12 =
18Total amount of money received
= 42 u + 6 u + 3 u
= 51 u
51 u = 561
1 u = 561 ÷ 51 = 11
Number of people who received the money
= 6 u + 1 u + 1 u
= 8 u
= 8 x 11
= 88
Answer(s): 88