David and Rael shared $42 equally. How much money must David give to Rael so that Rael will have five times as much money as David?
| |
David |
Rael |
Total |
| Before |
21 |
21 |
42 |
| Change |
- 14 |
+ 14 |
|
| After |
1 u |
5 u |
42 |
Amount that each of them had at first
= 42 ÷ 2
= $21
Amount that David had = 1 u
Amount that Rael had = 5 u
Total amount that David and Rael
= 1 u + 5 u
= 6 u
6 u = 42
1 u = 42 ÷ 6 = 7
Amount that David must give to Rael
= 21 - 7
= $14
Answer(s): $14
