Gem and Dana had an equal number of coins at first. After Gem gave 3 coins to Dana, Dana had 21 coins. How many coins does Gem have in the end?
|
Gem |
Dana |
Before |
1 u |
1 u |
Change |
- 3 |
+ 3 |
After |
1 u - 3 |
21 |
Number of coins that Dana had at first
= 21 - 3
= 18
1 u = 18
Number of coins that Gem had at first = 18
Number of coins that Gem had in the end
= 1 u - 3
= 18 - 3
= 15
Answer(s): 15