Leah and Josiah had a total of 186 coins. Josiah had 2 times as many coins as Leah.
- How many coins did Leah have?
- How many coins did Josiah have?
(a)
Number of coins that Leah had = 1 u
Number of coins that Josiah had = 2 u
Total number of coins
= 2 u + 1 u
= 3 u
3 u = 186
1 u = 186 ÷ 3 = 62
Number of coins that Leah had
= 1 u
= 62
(b)
Number of coins that Josiah had
= 2 u
= 2 x 62
= 124
Answer(s): (a) 62; (b) 124