Abigail and Kaylee had an equal number of candy canes at first. After Abigail bought another 20 candy canes and Kaylee lost 18 candy canes, Abigail had thrice as many candy canes as Kaylee. Find the number of candy canes each of them had at first.
| |
Abigail |
Kaylee |
| Before |
3 u - 20 |
1 u + 18 |
| Change |
+ 20 |
- 18 |
| After |
3 u |
1 u |
The number of candy canes that Abigail and Kaylee at first is the same.
3 u - 20 = 1 u + 18
3 u - 1 u = 18 + 20
2 u = 38
1 u = 38 ÷ 2 = 19
Number of candy canes that each of them had at first
= 1 u + 18
= 19 + 18
= 37
Answer(s): 37
