Layla and Alexander had an equal number of sweets at first. After Layla bought another 16 sweets and Alexander lost 17 sweets, Layla had four times as many sweets as Alexander. Find the number of sweets each of them had at first.
| |
Layla |
Alexander |
| Before |
4 u - 16 |
1 u + 17 |
| Change |
+ 16 |
- 17 |
| After |
4 u |
1 u |
The number of sweets that Layla and Alexander at first is the same.
4 u - 16 = 1 u + 17
4 u - 1 u = 17 + 16
3 u = 33
1 u = 33 ÷ 3 = 11
Number of sweets that each of them had at first
= 1 u + 17
= 11 + 17
= 28
Answer(s): 28
