Avery and Caleb had an equal number of sweets at first. After Avery bought another 17 sweets and Caleb lost 10 sweets, Avery had four times as many sweets as Caleb. Find the number of sweets each of them had at first.
| |
Avery |
Caleb |
| Before |
4 u - 17 |
1 u + 10 |
| Change |
+ 17 |
- 10 |
| After |
4 u |
1 u |
The number of sweets that Avery and Caleb at first is the same.
4 u - 17 = 1 u + 10
4 u - 1 u = 10 + 17
3 u = 27
1 u = 27 ÷ 3 = 9
Number of sweets that each of them had at first
= 1 u + 10
= 9 + 10
= 19
Answer(s): 19
