Abi and Marion had an equal number of candy canes. After Abi bought another 27 candy canes and Marion bought another 7 candy canes, Abi had thrice as many candy canes as Marion. Find the number of candy canes that each of them had at first.
|
Abi |
Marion |
Before |
3 u - 27 |
1 u - 7 |
Change |
+ 27 |
+ 7 |
After |
3 u |
1 u |
The number of candy canes that Abi and Marion had at first is the same.
3 u - 27 = 1 u - 7
3 u - 1 u = 27 - 7
2 u = 20
1 u = 20 ÷ 2 = 10
Number of candy canes that each had at first
= 10 - 7
= 3
Answer(s): 3