Rael had $77, Ken had $49 and Luis had thrice the total amount of money Rael and Ken had. How much must Luis give to Rael and Ken so that each of them has an equal amount of money?
- Rael
- Ken
(a)
Total amount that Rael and Ken had
= 77 + 49
= $126
Amount that Luis had
= 3 x 126
= $378
Total amount that the 3 boys had
= 126 + 378
= $504
Amount that each of them must have so that each of them has an equal amount of money
= 504 ÷ 3
= $168
Amount that Luis must give to Rael
= 168 - 77
= $91
(b)
Amount that Luis must give to Ken
= 168 - 49
= $119
Answer(s): (a) $91; (b) $119
