Tom had $90, Luis had $42 and Howard had four times the total amount of money Tom and Luis had. How much must Howard give to Tom and Luis so that each of them has an equal amount of money?
- Tom
- Luis
(a)
Total amount that Tom and Luis had
= 90 + 42
= $132
Amount that Howard had
= 4 x 132
= $528
Total amount that the 3 boys had
= 132 + 528
= $660
Amount that each of them must have so that each of them has an equal amount of money
= 660 ÷ 3
= $220
Amount that Howard must give to Tom
= 220 - 90
= $130
(b)
Amount that Howard must give to Luis
= 220 - 42
= $178
Answer(s): (a) $130; (b) $178
