Ryan had $75, Xavier had $36 and Warren had thrice the total amount of money Ryan and Xavier had. How much must Warren give to Ryan and Xavier so that each of them has an equal amount of money?
- Ryan
- Xavier
(a)
Total amount that Ryan and Xavier had
= 75 + 36
= $111
Amount that Warren had
= 3 x 111
= $333
Total amount that the 3 boys had
= 111 + 333
= $444
Amount that each of them must have so that each of them has an equal amount of money
= 444 ÷ 3
= $148
Amount that Warren must give to Ryan
= 148 - 75
= $73
(b)
Amount that Warren must give to Xavier
= 148 - 36
= $112
Answer(s): (a) $73; (b) $112
