Eric had $98, Julian had $40 and Neave had twice the total amount of money Eric and Julian had. How much must Neave give to Eric and Julian so that each of them has an equal amount of money?
- Eric
- Julian
(a)
Total amount that Eric and Julian had
= 98 + 40
= $138
Amount that Neave had
= 2 x 138
= $276
Total amount that the 3 boys had
= 138 + 276
= $414
Amount that each of them must have so that each of them has an equal amount of money
= 414 ÷ 3
= $138
Amount that Neave must give to Eric
= 138 - 98
= $40
(b)
Amount that Neave must give to Julian
= 138 - 40
= $98
Answer(s): (a) $40; (b) $98
