Ryan had $71, Howard had $37 and Gabriel had five times the total amount of money Ryan and Howard had. How much must Gabriel give to Ryan and Howard so that each of them has an equal amount of money?
- Ryan
- Howard
(a)
Total amount that Ryan and Howard had
= 71 + 37
= $108
Amount that Gabriel had
= 5 x 108
= $540
Total amount that the 3 boys had
= 108 + 540
= $648
Amount that each of them must have so that each of them has an equal amount of money
= 648 ÷ 3
= $216
Amount that Gabriel must give to Ryan
= 216 - 71
= $145
(b)
Amount that Gabriel must give to Howard
= 216 - 37
= $179
Answer(s): (a) $145; (b) $179
