Bobby had $97, Luis had $42 and Paul had twice the total amount of money Bobby and Luis had. How much must Paul give to Bobby and Luis so that each of them has an equal amount of money?
- Bobby
- Luis
(a)
Total amount that Bobby and Luis had
= 97 + 42
= $139
Amount that Paul had
= 2 x 139
= $278
Total amount that the 3 boys had
= 139 + 278
= $417
Amount that each of them must have so that each of them has an equal amount of money
= 417 ÷ 3
= $139
Amount that Paul must give to Bobby
= 139 - 97
= $42
(b)
Amount that Paul must give to Luis
= 139 - 42
= $97
Answer(s): (a) $42; (b) $97
