Bullet Train B and Bullet Train C had a total of 95 passengers. When 28 passengers from Bullet Train B moved to Bullet Train C, Bullet Train B had 4 times as many passengers as Bullet Train C. How many passengers were there in Bullet Train B at first?
|
Bullet Train B |
Bullet Train C |
Total |
Before |
4 u + 28 |
1 u - 28 |
95 |
Change |
- 28 |
+ 28 |
|
After |
4 u |
1 u |
95 |
Total number of passengers
= 1 u + 4 u
= 5 u
5 u = 95
1 u = 95 ÷ 5 = 19
Number of passengers in Bullet Train B at first
= 4 u + 28
= 4 x 19 + 28
= 76 + 28
= 104
Answer(s): 104