Erika has 7 pens fewer than Dana but 18 pens more than Ivan. The three children have 127 pens altogether.
- How many pens does Ivan have?
- How many pens does Dana have?
(a)
Number of pens Dana has = 1 u
Number of pens Erika has = 1 u - 7
Number of pens Ivan has = 1 u - 7 - 18 = 1 u - 25
Total number of pens
= 1 u + 1 u - 7 + 1 u - 25
= 3 u - 32
3 u - 32 = 127
3 u = 127 + 32
3 u = 159
1 u = 159 ÷ 3 = 53
Number of pens that Ivan has
= 1 u - 25
= 53 - 25
= 28
(b)
Number of pens that Dana has
= 1 u
= 53
Answer(s): (a) 28; (b) 53
