Xuan has 10 marbles fewer than Min but 39 marbles more than Daniel. The three children have 235 marbles altogether.
- How many marbles does Daniel have?
- How many marbles does Min have?
(a)
Number of marbles Min has = 1 u
Number of marbles Xuan has = 1 u - 10
Number of marbles Daniel has = 1 u - 10 - 39 = 1 u - 49
Total number of marbles
= 1 u + 1 u - 10 + 1 u - 49
= 3 u - 59
3 u - 59 = 235
3 u = 235 + 59
3 u = 294
1 u = 294 ÷ 3 = 98
Number of marbles that Daniel has
= 1 u - 49
= 98 - 49
= 49
(b)
Number of marbles that Min has
= 1 u
= 98
Answer(s): (a) 49; (b) 98