Esther paid $130 for a windbreaker and a ring. The ring cost nine times as much as the windbreaker.
- Find the cost of the windbreaker.
- Find the cost of the ring.
(a)
Cost of 1 ring = 9 u
Cost of 1 windbreaker = 1 u
Total cost of 1 ring and 1 windbreaker
= 9 u + 1 u
= 10 u
10 u = $130
1 u = 130 ÷ 10 = 13
Cost of the windbreaker
= 1 u
= $13
(b)
Cost of the ring
= 9 u
= 9 x 13
= $117
Answer(s): (a) $13; (b) $117