Jane and Emma had the same number of coins. After Jane had given away 68 coins, Emma had 3 times as many coins as Jane. How many coins did each of them have at first?
| |
Jane |
Emma |
| Before |
1 u + 68 |
3 u |
| Change |
- 68 |
|
| After |
1 u |
3 u |
Number of coins that Emma had remains unchanged.
Number of coins that Jane and Emma had at first is equal.
3 u = 1 u + 68
3 u - 1 u = 68
2 u = 68
1 u = 68 ÷ 2= 34
Number of coins that each of them had at first
= 1 u + 68
= 34 + 68
= 102
Answer(s): 102
