Hilda and Betty had the same number of coins. After Hilda had given away 60 coins, Betty had 5 times as many coins as Hilda. How many coins did each of them have at first?
| |
Hilda |
Betty |
| Before |
1 u + 60 |
5 u |
| Change |
- 60 |
|
| After |
1 u |
5 u |
Number of coins that Betty had remains unchanged.
Number of coins that Hilda and Betty had at first is equal.
5 u = 1 u + 60
5 u - 1 u = 60
4 u = 60
1 u = 60 ÷ 4= 15
Number of coins that each of them had at first
= 1 u + 60
= 15 + 60
= 75
Answer(s): 75
