Marion and Elyse had the same number of beads. After Marion had given away 66 beads, Elyse had 4 times as many beads as Marion. How many beads did each of them have at first?
| |
Marion |
Elyse |
| Before |
1 u + 66 |
4 u |
| Change |
- 66 |
|
| After |
1 u |
4 u |
Number of beads that Elyse had remains unchanged.
Number of beads that Marion and Elyse had at first is equal.
4 u = 1 u + 66
4 u - 1 u = 66
3 u = 66
1 u = 66 ÷ 3= 22
Number of beads that each of them had at first
= 1 u + 66
= 22 + 66
= 88
Answer(s): 88
