Jen and Abi had the same number of coins. After Jen had given away 72 coins, Abi had 9 times as many coins as Jen. How many coins did each of them have at first?
| |
Jen |
Abi |
| Before |
1 u + 72 |
9 u |
| Change |
- 72 |
|
| After |
1 u |
9 u |
Number of coins that Abi had remains unchanged.
Number of coins that Jen and Abi had at first is equal.
9 u = 1 u + 72
9 u - 1 u = 72
8 u = 72
1 u = 72 ÷ 8= 9
Number of coins that each of them had at first
= 1 u + 72
= 9 + 72
= 81
Answer(s): 81
