Xuan and Tammy had the same number of coins. After Xuan had given away 72 coins, Tammy had 7 times as many coins as Xuan. How many coins did each of them have at first?
| |
Xuan |
Tammy |
| Before |
1 u + 72 |
7 u |
| Change |
- 72 |
|
| After |
1 u |
7 u |
Number of coins that Tammy had remains unchanged.
Number of coins that Xuan and Tammy had at first is equal.
7 u = 1 u + 72
7 u - 1 u = 72
6 u = 72
1 u = 72 ÷ 6= 12
Number of coins that each of them had at first
= 1 u + 72
= 12 + 72
= 84
Answer(s): 84
