Linda and Tammy had the same number of coins. After Linda had given away 80 coins, Tammy had 6 times as many coins as Linda. How many coins did each of them have at first?
| |
Linda |
Tammy |
| Before |
1 u + 80 |
6 u |
| Change |
- 80 |
|
| After |
1 u |
6 u |
Number of coins that Tammy had remains unchanged.
Number of coins that Linda and Tammy had at first is equal.
6 u = 1 u + 80
6 u - 1 u = 80
5 u = 80
1 u = 80 ÷ 5= 16
Number of coins that each of them had at first
= 1 u + 80
= 16 + 80
= 96
Answer(s): 96
