Kathy and Xuan had the same number of beads. After Kathy had given away 66 beads, Xuan had 7 times as many beads as Kathy. How many beads did each of them have at first?
| |
Kathy |
Xuan |
| Before |
1 u + 66 |
7 u |
| Change |
- 66 |
|
| After |
1 u |
7 u |
Number of beads that Xuan had remains unchanged.
Number of beads that Kathy and Xuan had at first is equal.
7 u = 1 u + 66
7 u - 1 u = 66
6 u = 66
1 u = 66 ÷ 6= 11
Number of beads that each of them had at first
= 1 u + 66
= 11 + 66
= 77
Answer(s): 77
