Gillian and Abi had the same number of coins. After Gillian had given away 66 coins, Abi had 3 times as many coins as Gillian. How many coins did each of them have at first?
| |
Gillian |
Abi |
| Before |
1 u + 66 |
3 u |
| Change |
- 66 |
|
| After |
1 u |
3 u |
Number of coins that Abi had remains unchanged.
Number of coins that Gillian and Abi had at first is equal.
3 u = 1 u + 66
3 u - 1 u = 66
2 u = 66
1 u = 66 ÷ 2= 33
Number of coins that each of them had at first
= 1 u + 66
= 33 + 66
= 99
Answer(s): 99
