John and Xylia had the same number of sweets. After Xylia gave away 19 sweets and John gave away 47 sweets, Xylia had 5 times as many sweets as John. How many sweets did each of them have at first?
| |
John |
Xylia |
| Before |
1 u + 47 |
5 u + 19 |
| Change |
- 47 |
- 19 |
| After |
1 u |
5 u |
The number of sweets that John and Xylia had at first is the same.
5 u + 19 = 1 u + 47
5 u - 1 u = 47 - 19
4 u = 28
1 u = 28 ÷ 4 = 7
Number of sweets that each of them had at first
= 1 u + 47
= 7 + 47
= 54
Answer(s): 54
