Ken and Mary had the same number of sweets. After Mary gave away 20 sweets and Ken gave away 40 sweets, Mary had 6 times as many sweets as Ken. How many sweets did each of them have at first?
| |
Ken |
Mary |
| Before |
1 u + 40 |
6 u + 20 |
| Change |
- 40 |
- 20 |
| After |
1 u |
6 u |
The number of sweets that Ken and Mary had at first is the same.
6 u + 20 = 1 u + 40
6 u - 1 u = 40 - 20
5 u = 20
1 u = 20 ÷ 5 = 4
Number of sweets that each of them had at first
= 1 u + 40
= 4 + 40
= 44
Answer(s): 44
