Simon and Opal had the same number of sweets. After Opal gave away 21 sweets and Simon gave away 48 sweets, Opal had 2 times as many sweets as Simon. How many sweets did each of them have at first?
| |
Simon |
Opal |
| Before |
1 u + 48 |
2 u + 21 |
| Change |
- 48 |
- 21 |
| After |
1 u |
2 u |
The number of sweets that Simon and Opal had at first is the same.
2 u + 21 = 1 u + 48
2 u - 1 u = 48 - 21
1 u = 27
1 u = 27 ÷ 1 = 27
Number of sweets that each of them had at first
= 1 u + 48
= 27 + 48
= 75
Answer(s): 75
