Tom and Risa had the same number of sweets. After Risa gave away 21 sweets and Tom gave away 53 sweets, Risa had 3 times as many sweets as Tom. How many sweets did each of them have at first?
| |
Tom |
Risa |
| Before |
1 u + 53 |
3 u + 21 |
| Change |
- 53 |
- 21 |
| After |
1 u |
3 u |
The number of sweets that Tom and Risa had at first is the same.
3 u + 21 = 1 u + 53
3 u - 1 u = 53 - 21
2 u = 32
1 u = 32 ÷ 2 = 16
Number of sweets that each of them had at first
= 1 u + 53
= 16 + 53
= 69
Answer(s): 69
