Ken and Opal had the same number of sweets. After Opal gave away 15 sweets and Ken gave away 50 sweets, Opal had 6 times as many sweets as Ken. How many sweets did each of them have at first?
| |
Ken |
Opal |
| Before |
1 u + 50 |
6 u + 15 |
| Change |
- 50 |
- 15 |
| After |
1 u |
6 u |
The number of sweets that Ken and Opal had at first is the same.
6 u + 15 = 1 u + 50
6 u - 1 u = 50 - 15
5 u = 35
1 u = 35 ÷ 5 = 7
Number of sweets that each of them had at first
= 1 u + 50
= 7 + 50
= 57
Answer(s): 57
